\(\int \frac {a+a \sec (c+d x)}{\sqrt {e \cot (c+d x)}} \, dx\) [236]

Optimal result

Integrand size = 23, antiderivative size = 299 \[ \int \frac {a+a \sec (c+d x)}{\sqrt {e \cot (c+d x)}} \, dx=\frac {2 a \sin (c+d x)}{d \sqrt {e \cot (c+d x)}}-\frac {2 a \cos (c+d x) E\left (\left .c-\frac {\pi }{4}+d x\right |2\right )}{d \sqrt {e \cot (c+d x)} \sqrt {\sin (2 c+2 d x)}}-\frac {a \arctan \left (1-\sqrt {2} \sqrt {\tan (c+d x)}\right )}{\sqrt {2} d \sqrt {e \cot (c+d x)} \sqrt {\tan (c+d x)}}+\frac {a \arctan \left (1+\sqrt {2} \sqrt {\tan (c+d x)}\right )}{\sqrt {2} d \sqrt {e \cot (c+d x)} \sqrt {\tan (c+d x)}}+\frac {a \log \left (1-\sqrt {2} \sqrt {\tan (c+d x)}+\tan (c+d x)\right )}{2 \sqrt {2} d \sqrt {e \cot (c+d x)} \sqrt {\tan (c+d x)}}-\frac {a \log \left (1+\sqrt {2} \sqrt {\tan (c+d x)}+\tan (c+d x)\right )}{2 \sqrt {2} d \sqrt {e \cot (c+d x)} \sqrt {\tan (c+d x)}} \]

[Out]

2*a*sin(d*x+c)/d/(e*cot(d*x+c))^(1/2)+2*a*cos(d*x+c)*(sin(c+1/4*Pi+d*x)^2)^(1/2)/sin(c+1/4*Pi+d*x)*EllipticE(c
os(c+1/4*Pi+d*x),2^(1/2))/d/(e*cot(d*x+c))^(1/2)/sin(2*d*x+2*c)^(1/2)+1/2*a*arctan(-1+2^(1/2)*tan(d*x+c)^(1/2)
)/d*2^(1/2)/(e*cot(d*x+c))^(1/2)/tan(d*x+c)^(1/2)+1/2*a*arctan(1+2^(1/2)*tan(d*x+c)^(1/2))/d*2^(1/2)/(e*cot(d*
x+c))^(1/2)/tan(d*x+c)^(1/2)+1/4*a*ln(1-2^(1/2)*tan(d*x+c)^(1/2)+tan(d*x+c))/d*2^(1/2)/(e*cot(d*x+c))^(1/2)/ta
n(d*x+c)^(1/2)-1/4*a*ln(1+2^(1/2)*tan(d*x+c)^(1/2)+tan(d*x+c))/d*2^(1/2)/(e*cot(d*x+c))^(1/2)/tan(d*x+c)^(1/2)

Rubi [A] (verified)

Time = 0.31 (sec) , antiderivative size = 299, normalized size of antiderivative = 1.00, number of steps used = 17, number of rules used = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.609, Rules used = {3985, 3969, 3557, 335, 303, 1176, 631, 210, 1179, 642, 2693, 2695, 2652, 2719} \[ \int \frac {a+a \sec (c+d x)}{\sqrt {e \cot (c+d x)}} \, dx=-\frac {a \arctan \left (1-\sqrt {2} \sqrt {\tan (c+d x)}\right )}{\sqrt {2} d \sqrt {\tan (c+d x)} \sqrt {e \cot (c+d x)}}+\frac {a \arctan \left (\sqrt {2} \sqrt {\tan (c+d x)}+1\right )}{\sqrt {2} d \sqrt {\tan (c+d x)} \sqrt {e \cot (c+d x)}}+\frac {2 a \sin (c+d x)}{d \sqrt {e \cot (c+d x)}}+\frac {a \log \left (\tan (c+d x)-\sqrt {2} \sqrt {\tan (c+d x)}+1\right )}{2 \sqrt {2} d \sqrt {\tan (c+d x)} \sqrt {e \cot (c+d x)}}-\frac {a \log \left (\tan (c+d x)+\sqrt {2} \sqrt {\tan (c+d x)}+1\right )}{2 \sqrt {2} d \sqrt {\tan (c+d x)} \sqrt {e \cot (c+d x)}}-\frac {2 a \cos (c+d x) E\left (\left .c+d x-\frac {\pi }{4}\right |2\right )}{d \sqrt {\sin (2 c+2 d x)} \sqrt {e \cot (c+d x)}} \]

[In]

Int[(a + a*Sec[c + d*x])/Sqrt[e*Cot[c + d*x]],x]

[Out]

(2*a*Sin[c + d*x])/(d*Sqrt[e*Cot[c + d*x]]) - (2*a*Cos[c + d*x]*EllipticE[c - Pi/4 + d*x, 2])/(d*Sqrt[e*Cot[c
+ d*x]]*Sqrt[Sin[2*c + 2*d*x]]) - (a*ArcTan[1 - Sqrt[2]*Sqrt[Tan[c + d*x]]])/(Sqrt[2]*d*Sqrt[e*Cot[c + d*x]]*S
qrt[Tan[c + d*x]]) + (a*ArcTan[1 + Sqrt[2]*Sqrt[Tan[c + d*x]]])/(Sqrt[2]*d*Sqrt[e*Cot[c + d*x]]*Sqrt[Tan[c + d
*x]]) + (a*Log[1 - Sqrt[2]*Sqrt[Tan[c + d*x]] + Tan[c + d*x]])/(2*Sqrt[2]*d*Sqrt[e*Cot[c + d*x]]*Sqrt[Tan[c +
d*x]]) - (a*Log[1 + Sqrt[2]*Sqrt[Tan[c + d*x]] + Tan[c + d*x]])/(2*Sqrt[2]*d*Sqrt[e*Cot[c + d*x]]*Sqrt[Tan[c +
d*x]])

Rule 210

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^(-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])
], x] /; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 303

Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[a/b, 2]], s = Denominator[Rt[a/b, 2]]},
Dist[1/(2*s), Int[(r + s*x^2)/(a + b*x^4), x], x] - Dist[1/(2*s), Int[(r - s*x^2)/(a + b*x^4), x], x]] /; Free
Q[{a, b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] && AtomQ[SplitProduct[SumBaseQ,
b]]))

Rule 335

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = Denominator[m]}, Dist[k/c, Subst[I
nt[x^(k*(m + 1) - 1)*(a + b*(x^(k*n)/c^n))^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0]
&& FractionQ[m] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 631

Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*Simplify[a*(c/b^2)]}, Dist[-2/b, Sub
st[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b)], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /;
FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 642

Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Simp[d*(Log[RemoveContent[a + b*x +
c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]

Rule 1176

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[2*(d/e), 2]}, Dist[e/(2*c), Int[1/S
imp[d/e + q*x + x^2, x], x], x] + Dist[e/(2*c), Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e},
x] && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]

Rule 1179

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[-2*(d/e), 2]}, Dist[e/(2*c*q), Int[
(q - 2*x)/Simp[d/e + q*x - x^2, x], x], x] + Dist[e/(2*c*q), Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /
; FreeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]

Rule 2652

Int[Sqrt[cos[(e_.) + (f_.)*(x_)]*(b_.)]*Sqrt[(a_.)*sin[(e_.) + (f_.)*(x_)]], x_Symbol] :> Dist[Sqrt[a*Sin[e +
f*x]]*(Sqrt[b*Cos[e + f*x]]/Sqrt[Sin[2*e + 2*f*x]]), Int[Sqrt[Sin[2*e + 2*f*x]], x], x] /; FreeQ[{a, b, e, f},
x]

Rule 2693

Int[((a_.)*sec[(e_.) + (f_.)*(x_)])^(m_.)*((b_.)*tan[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Simp[a^2*(a*Sec[e
+ f*x])^(m - 2)*((b*Tan[e + f*x])^(n + 1)/(b*f*(m + n - 1))), x] + Dist[a^2*((m - 2)/(m + n - 1)), Int[(a*Sec
[e + f*x])^(m - 2)*(b*Tan[e + f*x])^n, x], x] /; FreeQ[{a, b, e, f, n}, x] && (GtQ[m, 1] || (EqQ[m, 1] && EqQ[
n, 1/2])) && NeQ[m + n - 1, 0] && IntegersQ[2*m, 2*n]

Rule 2695

Int[Sqrt[(b_.)*tan[(e_.) + (f_.)*(x_)]]/sec[(e_.) + (f_.)*(x_)], x_Symbol] :> Dist[Sqrt[Cos[e + f*x]]*(Sqrt[b*
Tan[e + f*x]]/Sqrt[Sin[e + f*x]]), Int[Sqrt[Cos[e + f*x]]*Sqrt[Sin[e + f*x]], x], x] /; FreeQ[{b, e, f}, x]

Rule 2719

Int[Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/d)*EllipticE[(1/2)*(c - Pi/2 + d*x), 2], x] /; FreeQ[{
c, d}, x]

Rule 3557

Int[((b_.)*tan[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Dist[b/d, Subst[Int[x^n/(b^2 + x^2), x], x, b*Tan[c + d
*x]], x] /; FreeQ[{b, c, d, n}, x] &&  !IntegerQ[n]

Rule 3969

Int[(cot[(c_.) + (d_.)*(x_)]*(e_.))^(m_.)*(csc[(c_.) + (d_.)*(x_)]*(b_.) + (a_)), x_Symbol] :> Dist[a, Int[(e*
Cot[c + d*x])^m, x], x] + Dist[b, Int[(e*Cot[c + d*x])^m*Csc[c + d*x], x], x] /; FreeQ[{a, b, c, d, e, m}, x]

Rule 3985

Int[(cot[(c_.) + (d_.)*(x_)]*(e_.))^(m_)*((a_) + (b_.)*sec[(c_.) + (d_.)*(x_)])^(n_.), x_Symbol] :> Dist[(e*Co
t[c + d*x])^m*Tan[c + d*x]^m, Int[(a + b*Sec[c + d*x])^n/Tan[c + d*x]^m, x], x] /; FreeQ[{a, b, c, d, e, m, n}
, x] &&  !IntegerQ[m]

Rubi steps \begin{align*} \text {integral}& = \frac {\int (a+a \sec (c+d x)) \sqrt {\tan (c+d x)} \, dx}{\sqrt {e \cot (c+d x)} \sqrt {\tan (c+d x)}} \\ & = \frac {a \int \sqrt {\tan (c+d x)} \, dx}{\sqrt {e \cot (c+d x)} \sqrt {\tan (c+d x)}}+\frac {a \int \sec (c+d x) \sqrt {\tan (c+d x)} \, dx}{\sqrt {e \cot (c+d x)} \sqrt {\tan (c+d x)}} \\ & = \frac {2 a \sin (c+d x)}{d \sqrt {e \cot (c+d x)}}-\frac {(2 a) \int \cos (c+d x) \sqrt {\tan (c+d x)} \, dx}{\sqrt {e \cot (c+d x)} \sqrt {\tan (c+d x)}}+\frac {a \text {Subst}\left (\int \frac {\sqrt {x}}{1+x^2} \, dx,x,\tan (c+d x)\right )}{d \sqrt {e \cot (c+d x)} \sqrt {\tan (c+d x)}} \\ & = \frac {2 a \sin (c+d x)}{d \sqrt {e \cot (c+d x)}}-\frac {\left (2 a \sqrt {\cos (c+d x)}\right ) \int \sqrt {\cos (c+d x)} \sqrt {\sin (c+d x)} \, dx}{\sqrt {e \cot (c+d x)} \sqrt {\sin (c+d x)}}+\frac {(2 a) \text {Subst}\left (\int \frac {x^2}{1+x^4} \, dx,x,\sqrt {\tan (c+d x)}\right )}{d \sqrt {e \cot (c+d x)} \sqrt {\tan (c+d x)}} \\ & = \frac {2 a \sin (c+d x)}{d \sqrt {e \cot (c+d x)}}-\frac {(2 a \cos (c+d x)) \int \sqrt {\sin (2 c+2 d x)} \, dx}{\sqrt {e \cot (c+d x)} \sqrt {\sin (2 c+2 d x)}}-\frac {a \text {Subst}\left (\int \frac {1-x^2}{1+x^4} \, dx,x,\sqrt {\tan (c+d x)}\right )}{d \sqrt {e \cot (c+d x)} \sqrt {\tan (c+d x)}}+\frac {a \text {Subst}\left (\int \frac {1+x^2}{1+x^4} \, dx,x,\sqrt {\tan (c+d x)}\right )}{d \sqrt {e \cot (c+d x)} \sqrt {\tan (c+d x)}} \\ & = \frac {2 a \sin (c+d x)}{d \sqrt {e \cot (c+d x)}}-\frac {2 a \cos (c+d x) E\left (\left .c-\frac {\pi }{4}+d x\right |2\right )}{d \sqrt {e \cot (c+d x)} \sqrt {\sin (2 c+2 d x)}}+\frac {a \text {Subst}\left (\int \frac {1}{1-\sqrt {2} x+x^2} \, dx,x,\sqrt {\tan (c+d x)}\right )}{2 d \sqrt {e \cot (c+d x)} \sqrt {\tan (c+d x)}}+\frac {a \text {Subst}\left (\int \frac {1}{1+\sqrt {2} x+x^2} \, dx,x,\sqrt {\tan (c+d x)}\right )}{2 d \sqrt {e \cot (c+d x)} \sqrt {\tan (c+d x)}}+\frac {a \text {Subst}\left (\int \frac {\sqrt {2}+2 x}{-1-\sqrt {2} x-x^2} \, dx,x,\sqrt {\tan (c+d x)}\right )}{2 \sqrt {2} d \sqrt {e \cot (c+d x)} \sqrt {\tan (c+d x)}}+\frac {a \text {Subst}\left (\int \frac {\sqrt {2}-2 x}{-1+\sqrt {2} x-x^2} \, dx,x,\sqrt {\tan (c+d x)}\right )}{2 \sqrt {2} d \sqrt {e \cot (c+d x)} \sqrt {\tan (c+d x)}} \\ & = \frac {2 a \sin (c+d x)}{d \sqrt {e \cot (c+d x)}}-\frac {2 a \cos (c+d x) E\left (\left .c-\frac {\pi }{4}+d x\right |2\right )}{d \sqrt {e \cot (c+d x)} \sqrt {\sin (2 c+2 d x)}}+\frac {a \log \left (1-\sqrt {2} \sqrt {\tan (c+d x)}+\tan (c+d x)\right )}{2 \sqrt {2} d \sqrt {e \cot (c+d x)} \sqrt {\tan (c+d x)}}-\frac {a \log \left (1+\sqrt {2} \sqrt {\tan (c+d x)}+\tan (c+d x)\right )}{2 \sqrt {2} d \sqrt {e \cot (c+d x)} \sqrt {\tan (c+d x)}}+\frac {a \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\sqrt {2} \sqrt {\tan (c+d x)}\right )}{\sqrt {2} d \sqrt {e \cot (c+d x)} \sqrt {\tan (c+d x)}}-\frac {a \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\sqrt {2} \sqrt {\tan (c+d x)}\right )}{\sqrt {2} d \sqrt {e \cot (c+d x)} \sqrt {\tan (c+d x)}} \\ & = \frac {2 a \sin (c+d x)}{d \sqrt {e \cot (c+d x)}}-\frac {2 a \cos (c+d x) E\left (\left .c-\frac {\pi }{4}+d x\right |2\right )}{d \sqrt {e \cot (c+d x)} \sqrt {\sin (2 c+2 d x)}}-\frac {a \arctan \left (1-\sqrt {2} \sqrt {\tan (c+d x)}\right )}{\sqrt {2} d \sqrt {e \cot (c+d x)} \sqrt {\tan (c+d x)}}+\frac {a \arctan \left (1+\sqrt {2} \sqrt {\tan (c+d x)}\right )}{\sqrt {2} d \sqrt {e \cot (c+d x)} \sqrt {\tan (c+d x)}}+\frac {a \log \left (1-\sqrt {2} \sqrt {\tan (c+d x)}+\tan (c+d x)\right )}{2 \sqrt {2} d \sqrt {e \cot (c+d x)} \sqrt {\tan (c+d x)}}-\frac {a \log \left (1+\sqrt {2} \sqrt {\tan (c+d x)}+\tan (c+d x)\right )}{2 \sqrt {2} d \sqrt {e \cot (c+d x)} \sqrt {\tan (c+d x)}} \\ \end{align*}

Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.

Time = 1.42 (sec) , antiderivative size = 189, normalized size of antiderivative = 0.63 \[ \int \frac {a+a \sec (c+d x)}{\sqrt {e \cot (c+d x)}} \, dx=\frac {a (1+\cos (c+d x)) \sec ^2\left (\frac {1}{2} (c+d x)\right ) \sec (c+d x) \left (8 \cot ^3(c+d x) \operatorname {Hypergeometric2F1}\left (\frac {3}{4},\frac {3}{2},\frac {7}{4},-\cot ^2(c+d x)\right )-3 \cot (c+d x) \sqrt {\csc ^2(c+d x)} \left (-2+2 \cos (2 (c+d x))+\arcsin (\cos (c+d x)-\sin (c+d x)) \sqrt {\sin (2 (c+d x))}+\log \left (\cos (c+d x)+\sin (c+d x)+\sqrt {\sin (2 (c+d x))}\right ) \sqrt {\sin (2 (c+d x))}\right )\right )}{12 d \sqrt {e \cot (c+d x)} \sqrt {\csc ^2(c+d x)}} \]

[In]

Integrate[(a + a*Sec[c + d*x])/Sqrt[e*Cot[c + d*x]],x]

[Out]

(a*(1 + Cos[c + d*x])*Sec[(c + d*x)/2]^2*Sec[c + d*x]*(8*Cot[c + d*x]^3*Hypergeometric2F1[3/4, 3/2, 7/4, -Cot[
c + d*x]^2] - 3*Cot[c + d*x]*Sqrt[Csc[c + d*x]^2]*(-2 + 2*Cos[2*(c + d*x)] + ArcSin[Cos[c + d*x] - Sin[c + d*x
]]*Sqrt[Sin[2*(c + d*x)]] + Log[Cos[c + d*x] + Sin[c + d*x] + Sqrt[Sin[2*(c + d*x)]]]*Sqrt[Sin[2*(c + d*x)]]))
)/(12*d*Sqrt[e*Cot[c + d*x]]*Sqrt[Csc[c + d*x]^2])

Maple [A] (verified)

Time = 10.38 (sec) , antiderivative size = 507, normalized size of antiderivative = 1.70

method	result	size
parts	\(-\frac {a \left (e^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {e \cot \left (d x +c \right )+\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}{e \cot \left (d x +c \right )-\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{4 d e}-\frac {a \sqrt {2}\, \left (-2 \sqrt {\csc \left (d x +c \right )-\cot \left (d x +c \right )+1}\, \sqrt {\cot \left (d x +c \right )-\csc \left (d x +c \right )+1}\, \sqrt {\cot \left (d x +c \right )-\csc \left (d x +c \right )}\, \operatorname {EllipticE}\left (\sqrt {\csc \left (d x +c \right )-\cot \left (d x +c \right )+1}, \frac {\sqrt {2}}{2}\right ) \cos \left (d x +c \right )+\sqrt {\csc \left (d x +c \right )-\cot \left (d x +c \right )+1}\, \sqrt {\cot \left (d x +c \right )-\csc \left (d x +c \right )+1}\, \sqrt {\cot \left (d x +c \right )-\csc \left (d x +c \right )}\, \operatorname {EllipticF}\left (\sqrt {\csc \left (d x +c \right )-\cot \left (d x +c \right )+1}, \frac {\sqrt {2}}{2}\right ) \cos \left (d x +c \right )-2 \sqrt {\csc \left (d x +c \right )-\cot \left (d x +c \right )+1}\, \sqrt {\cot \left (d x +c \right )-\csc \left (d x +c \right )+1}\, \sqrt {\cot \left (d x +c \right )-\csc \left (d x +c \right )}\, \operatorname {EllipticE}\left (\sqrt {\csc \left (d x +c \right )-\cot \left (d x +c \right )+1}, \frac {\sqrt {2}}{2}\right )+\sqrt {\csc \left (d x +c \right )-\cot \left (d x +c \right )+1}\, \sqrt {\cot \left (d x +c \right )-\csc \left (d x +c \right )+1}\, \sqrt {\cot \left (d x +c \right )-\csc \left (d x +c \right )}\, \operatorname {EllipticF}\left (\sqrt {\csc \left (d x +c \right )-\cot \left (d x +c \right )+1}, \frac {\sqrt {2}}{2}\right )+\sqrt {2}\, \cos \left (d x +c \right )-\sqrt {2}\right ) \csc \left (d x +c \right )}{d \sqrt {e \cot \left (d x +c \right )}}\)	\(507\)
default	\(\text {Expression too large to display}\)	\(1051\)

[In]

int((a+a*sec(d*x+c))/(e*cot(d*x+c))^(1/2),x,method=_RETURNVERBOSE)

[Out]

-1/4*a/d/e*(e^2)^(1/4)*2^(1/2)*(ln((e*cot(d*x+c)+(e^2)^(1/4)*(e*cot(d*x+c))^(1/2)*2^(1/2)+(e^2)^(1/2))/(e*cot(
d*x+c)-(e^2)^(1/4)*(e*cot(d*x+c))^(1/2)*2^(1/2)+(e^2)^(1/2)))+2*arctan(2^(1/2)/(e^2)^(1/4)*(e*cot(d*x+c))^(1/2
)+1)-2*arctan(-2^(1/2)/(e^2)^(1/4)*(e*cot(d*x+c))^(1/2)+1))-a/d*2^(1/2)*(-2*(csc(d*x+c)-cot(d*x+c)+1)^(1/2)*(c
ot(d*x+c)-csc(d*x+c)+1)^(1/2)*(cot(d*x+c)-csc(d*x+c))^(1/2)*EllipticE((csc(d*x+c)-cot(d*x+c)+1)^(1/2),1/2*2^(1
/2))*cos(d*x+c)+(csc(d*x+c)-cot(d*x+c)+1)^(1/2)*(cot(d*x+c)-csc(d*x+c)+1)^(1/2)*(cot(d*x+c)-csc(d*x+c))^(1/2)*
EllipticF((csc(d*x+c)-cot(d*x+c)+1)^(1/2),1/2*2^(1/2))*cos(d*x+c)-2*(csc(d*x+c)-cot(d*x+c)+1)^(1/2)*(cot(d*x+c
)-csc(d*x+c)+1)^(1/2)*(cot(d*x+c)-csc(d*x+c))^(1/2)*EllipticE((csc(d*x+c)-cot(d*x+c)+1)^(1/2),1/2*2^(1/2))+(cs
c(d*x+c)-cot(d*x+c)+1)^(1/2)*(cot(d*x+c)-csc(d*x+c)+1)^(1/2)*(cot(d*x+c)-csc(d*x+c))^(1/2)*EllipticF((csc(d*x+
c)-cot(d*x+c)+1)^(1/2),1/2*2^(1/2))+2^(1/2)*cos(d*x+c)-2^(1/2))/(e*cot(d*x+c))^(1/2)*csc(d*x+c)

Fricas [F(-1)]

Timed out. \[ \int \frac {a+a \sec (c+d x)}{\sqrt {e \cot (c+d x)}} \, dx=\text {Timed out} \]

[In]

integrate((a+a*sec(d*x+c))/(e*cot(d*x+c))^(1/2),x, algorithm="fricas")

[Out]

Timed out

Sympy [F]

\[ \int \frac {a+a \sec (c+d x)}{\sqrt {e \cot (c+d x)}} \, dx=a \left (\int \frac {1}{\sqrt {e \cot {\left (c + d x \right )}}}\, dx + \int \frac {\sec {\left (c + d x \right )}}{\sqrt {e \cot {\left (c + d x \right )}}}\, dx\right ) \]

[In]

integrate((a+a*sec(d*x+c))/(e*cot(d*x+c))**(1/2),x)

[Out]

a*(Integral(1/sqrt(e*cot(c + d*x)), x) + Integral(sec(c + d*x)/sqrt(e*cot(c + d*x)), x))

Maxima [F(-2)]

Exception generated. \[ \int \frac {a+a \sec (c+d x)}{\sqrt {e \cot (c+d x)}} \, dx=\text {Exception raised: ValueError} \]

[In]

integrate((a+a*sec(d*x+c))/(e*cot(d*x+c))^(1/2),x, algorithm="maxima")

[Out]

Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'a
ssume' command before evaluation *may* help (example of legal syntax is 'assume(e>0)', see `assume?` for more
details)Is e

Giac [F]

\[ \int \frac {a+a \sec (c+d x)}{\sqrt {e \cot (c+d x)}} \, dx=\int { \frac {a \sec \left (d x + c\right ) + a}{\sqrt {e \cot \left (d x + c\right )}} \,d x } \]

[In]

integrate((a+a*sec(d*x+c))/(e*cot(d*x+c))^(1/2),x, algorithm="giac")

[Out]

integrate((a*sec(d*x + c) + a)/sqrt(e*cot(d*x + c)), x)

Mupad [F(-1)]

Timed out. \[ \int \frac {a+a \sec (c+d x)}{\sqrt {e \cot (c+d x)}} \, dx=\int \frac {a+\frac {a}{\cos \left (c+d\,x\right )}}{\sqrt {e\,\mathrm {cot}\left (c+d\,x\right )}} \,d x \]

[In]

int((a + a/cos(c + d*x))/(e*cot(c + d*x))^(1/2),x)

[Out]

int((a + a/cos(c + d*x))/(e*cot(c + d*x))^(1/2), x)